a boy does 400j of work in 20sec in the firsr time and during second time the same boy does 100j of work in 2sec find the ratio of the power delivered by the boy in both the part.
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Power = Work / Time
So,
P₁/P₂ = W₁/W₂ × T₂/T₁
= [(400 J) / (100 J)] × [(2 s) / (20 s)]
= 4 / 10
= 2 / 5
= 2 : 5
Ratio of power = 2 : 5
So,
P₁/P₂ = W₁/W₂ × T₂/T₁
= [(400 J) / (100 J)] × [(2 s) / (20 s)]
= 4 / 10
= 2 / 5
= 2 : 5
Ratio of power = 2 : 5
shivam461:
thank uu so much
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