Math, asked by F41, 2 months ago

A boy gets Rs .2 for every 5 correct aims at a target loses Rs. 0.50 for every aim missed . In a game of 8 trials he missed the aim 3 times. how much amount does he get​

Answers

Answered by Anonymous
15

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Let’s take correct aims to be ‘a’,

fails be ‘f’.

Here, f = 3.

Therefore, as per the problem statement,

Total attempts

= a + f = 8,

Thus,

a = 8 - 3

= 5.

So, Final amount

= (2 × a) - (0.5 × f)

or, Final amount

= (2 × 5) - (3 × 0.5)

= 10 - 1.5

= 8.5

Therefore, the final amount that he would get is Rs. 8.50.

Answered by TYKE
1

Answer:

The answer is ₹ 8.50.

Step-by-step explanation:

Let’s take correct aims to be ‘a’,

fails be ‘f’.

Here, f = 3.

Therefore, as per the problem statement,

Total attempts

= a + f = 8,

Thus,

a = 8 - 3

= 5.

So, Final amount

= (2 × a) - (0.5 × f)

or, Final amount

= (2 × 5) - (3 × 0.5)

= 10 - 1.5

= 8.5

Therefore, the final amount that he would get is Rs. 8.50.

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