Question

A boy goes from A to B with a velocity of 20 m/min and comes back from B to A with a velocity of 30 m/min. The average velocity of the boy during the whole journey is

Answer 1

Explanation:

Let the distance from A to B be x ,time taken be t1 and t2 and speeds be v1 and v2.

So, t1=x/v1 ————-(i)

And, t2=x/v2 ———(ii)

Now, according to the definition of average speed= Total distance/ total time

So, Vavg= 2x/[(x/v1)+(x/v2)]

Simplifying this you can write :-

Vavg= 2x/[x(v1+v2)/v1v2]

So, Vavg=2v1v2/(v1+v2)

Putting the values for v1=20m/s and v2=30m/s in the equation we can write :-

Vavg=(2×30×20)/50=24m/s.

In case of average velocity it is 0 m/s because the displacement is 0 as the body returns to its original position.

Thanks for reading.

Answer 2

Answer:

its 2/5 meter per sec

Explanation:

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