Question

A boy has 350 rupees in his bank account. He deposit 40 rupees everyday for 10 days. What will be the amount in his account at the end of 10 days? please explain with statement.
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Answer 1

Answer:

current amount = 350

amount deposited each day = 40

amount deposited in 10 days = 40 x 10 = 400

amount after 10 days = 350 + 400

                                = 750

Answer 2

Answer:

The amount of money in his account after 10 days = 750rupees

Step-by-step explanation:

Given,

The initial amount the boy has in account = 350

The amount he deposited for 10 days = 40

To find,

The amount in the account after 10days

Solution:

Recall the formula

The nth term of an AP = a+(n-1) d, where 'a' is the first term and 'd' is the common difference of the AP.

The amount of money in the account each day is given by

350,350+40,350+40+40,...........

This sequence form an AP with first term 350 and common difference d = 40

Since, he deposited Rs. 40 for 10 days, required to find the 11th term of this AP

$a_{11}$ = a+(11-1)d

= 350 + 10 ×40

= 350 + 400

$a_{11}$ = 750

∴ The amount of money in his account after 10 days = 750rupees

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