a boy has 728 is denominated of rupees 2 notes , rupees 5 notes and rupees 10 notes in the ratio of 3:2:4 , respectively . what is the total number of notes ?
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Answered by
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Let the number of notes be 3x, 2x, 4x,
2×3x+5×2x+10×4x=728
X=13
By placing value we get 39, 26, 52 notes of 2, 5, 10 denomination.
Hope u understood the question. .
2×3x+5×2x+10×4x=728
X=13
By placing value we get 39, 26, 52 notes of 2, 5, 10 denomination.
Hope u understood the question. .
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Answered by
1
Total rs 728
Notes of 2,5,10
Let x be common
So,
2x*3=6x
5x*2=10x
10x*4=40x
(6+10+40)x = 56x
56x= 728
x=13
Notes will be of
Rs 2 13*3=39
Rs 5 13*2=26
Rs10. 13*4=52
Notes of 2,5,10
Let x be common
So,
2x*3=6x
5x*2=10x
10x*4=40x
(6+10+40)x = 56x
56x= 728
x=13
Notes will be of
Rs 2 13*3=39
Rs 5 13*2=26
Rs10. 13*4=52
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