A boy has 728 rupees in denomination of 2 rupee notes , 5 rupee notes and 10 rupee notes in the ratio of 3:2:4 , respectively . what is the total number of notes he has ?
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Let the common multiple be x, then
6x+10x+40x = 728
56x = 728
x = 13
Therefore the total number of notes the boy has
= 3x
= 39
6x+10x+40x = 728
56x = 728
x = 13
Therefore the total number of notes the boy has
= 3x
= 39
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