A boy has 728 rupees in denomination of 2 rupee notes , 5 rupee notes and 10 rupee notes in the ratio of 3:2:4 , respectively . what is the total number of notes he has ?
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Answered by
0
Let the common multiple be x, then
6x+10x+40x = 728
56x = 728
x = 13
Therefore the total number of notes the boy has
= 3x
= 39
6x+10x+40x = 728
56x = 728
x = 13
Therefore the total number of notes the boy has
= 3x
= 39
Answered by
3
Let the ratios be in terms of x.
(2×3x)+(5×2x)+(4x×10) = 728
6x + 10x +40x = 728
56x = 728
x = 13.
Number of Notes = 39 + 26 + 52 = 117 notes
(2×3x)+(5×2x)+(4x×10) = 728
6x + 10x +40x = 728
56x = 728
x = 13.
Number of Notes = 39 + 26 + 52 = 117 notes
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