Question

A boy has a spherical ladoo whose radius is 4 cm . A girl has 8 spherical ladoos each of radius 2cm . find the ratio of volumes of ladoo girl has to the ladoo of boy

Answer 1

Here's your answer...

Answer 2

$Radius \:of \: spherical \: ladoo \: of \\a \:boy (R) = 4 \:cm$

$Radius \:of \: each \: spherical \: ladoo \: of \\ a \:girl (r) = 2 \:cm$

$\red {ratio\: of \:volumes \:of \:ladoo\: girl}\\\red{ has\: to\: the\: ladoo \:of \:boy}$

$= \frac{8 \times \frac{4}{3} \pi r^{3} }{ \frac{4}{3} \pi R^{3} }\\= \frac{8 \times r^{3}}{ R^{3}} \\= \frac{ 8 \times 2^{3}}{ 4^{3}} \\= \frac{8\times 8}{64} \\= \frac{64}{64} \\= 1 : 1$

Therefore.,

$\red {ratio\: of \:volumes \:of \:ladoo\: girl}\\\red{ has\: to\: the\: ladoo \:of \:boy} \\\green {= 1 : 1 }$

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