A boy has rs728 in the denomination of rs2 notes,rs5 notes and rs10 notes in the ratio of 3:2:4 respectively.what is the total no of notes he has
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Rs.2 =3x*2=6x
Rs.5 =2x*5=10x
Rs.10 =10x*4=40x
6x+10x+40x=728
56x=728
x=728/56
x=13
Rs.2=3*13=39
Rs.5=2*13=26
Rs.10=4*13=52
Total no of notes = 39+26+52 =117
Rs.5 =2x*5=10x
Rs.10 =10x*4=40x
6x+10x+40x=728
56x=728
x=728/56
x=13
Rs.2=3*13=39
Rs.5=2*13=26
Rs.10=4*13=52
Total no of notes = 39+26+52 =117
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You will get two equations
2x+5y+10z=728 and
3x+2y+4z =9
Solve these to get the value of number of notes
2x+5y+10z=728 and
3x+2y+4z =9
Solve these to get the value of number of notes
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