Physics, asked by TbiaSamishta, 1 year ago

A boy holds a 40N weight at arm's length for 10s. His arm is 1.5 above the ground . the work done by the boy on the weight while he is holding it is

Answers

Answered by aqibkincsem
0

Work done is given by the equation: W=F⋅d ... W=40 N⋅1.5 m.  What if the boy walked across the room with the weight held in the position?


The boy holds a 40 N weight and takes place by arm length for 10ms.


His arm is 1.5m above ground and work done by force is at holding it accordingly.

Answered by kamalswami123lhu
9

work done is 0

Because there is no displacement^_^

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