Question

A boy is flying a kite with a string 42 meter
It makes an angle of us with the horizontal find the high of the kite from the background​

Answer 1

Answer:

Let the length of second string be x m

In ΔABC

sin30

∘

=

AB

AC

2

1

=

100

AC

⇒AC=50m

In ΔAEF

sin45

∘

=

AE

AF

2

1

=

x

AC−FC

2

1

=

x

50−10

[∵ AC = 50 m, FC = ED = 10 m]

2

1

=

x

40

x=40

2

m

∴ the length of string that the second boy must have so that the two kites meet = 40

2

m