(a boy is hanging from a horizontal branch of a tree . find the angle between the arms So that tension in the arms to be maximum)
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Answered by
34
We can simplify the system by assuming the boy to be a box hung by two strings making an angle between them.
Let angle between the strings be 2a
and tension in them be T (it wil be same in both due to symmetry)
Thus total force due to tension balancing the mass of block will be:
2T cos a = mg
T = mg/(2 cos a)
for minimum T we differentiate it with a.
Let angle between the strings be 2a
and tension in them be T (it wil be same in both due to symmetry)
Thus total force due to tension balancing the mass of block will be:
2T cos a = mg
T = mg/(2 cos a)
for minimum T we differentiate it with a.
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chinnu41:
pls send it once again it is saying answer doesnt exist
i will write it here
one min.
ok
dT/da = - (-sin a) mg/2cos sq a =0
therefore a = 0
wrong it is 120
is there any no. kg in the question
no that is question
u have done it for min tension but it is for max tension
Answered by
21
Answer:
Explanation:
Hope it will help u, 90° is not possible only when u imagine the situation.
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