Question

A Boy is Pulling a box with a force of 50N which makes an angle of 60 degree with the ground. It's perpendicular components are

A: 4.33N,25N
B:25N,43.3N
C:28.3N,40N
D:15.5N,35.5N​

Answer 1

Answer:

R = Resultant Force

Fy= Force at y

Fx= Force at x

R = Fx + Fy

Fx=50(?)

the Force in the x direction is given as 50 something.

the Force Resultant direction is 60 degrees from x axis

Fx=R cos(60)=50(?)

R = 50(?)/cos(60)

cos(60)=1/2

R= 100(?)

Fy=R sin(60)

sin (60)=square root of 3 / 2

Fy = 100 • square root of 3 / 2

Fy = 86.6(?)

Answer 2

Concept Introduction: Motion in two dimension are the vasic concepts of advanced physics.

Given:

We have been Given:

$f = 50n \\ \alpha = 60 \: degree$

To Find:

We have to Find: It's perpendicular components are?

Solution:

According to the problem, the perpendicular components are:

$50 \times \cos(60) = horizontal \: force \\ 50 \times \sin(60) = vertical \: force$

Simplifying we get,

$horizontal \: force \: = 50 \times \frac{1}{2} = 25n \\ vertical \: force = 50 \times 0.866 = 43.3n$

Final Answer:

Horizontal Force is

$25n$

Vertical Force is

$43.3n$

Correct Option is Option No. B

#SPJ2