Question

A boy is pushing a ring of mass 2 kg and radius 0.5 m with a stick as shown in the figure. The stick applied a force of 2 N on the ring and rolls it without slipping with an acceleration of 0.3 m/s2. The coefficient of friction between the ground and the ring is large enough that rolling always occurs and the coefficient of friction between the stick and the ring is (P/10). The value of P is

Answer 1

Thank you for asking this question.

The writing equation for torque and force of the ring

N₁ - f₂ = ma this will be one equation

N₂ - f₁ = mg this will be second equation

(f₂ - f₁) r = mr² α this will be equation 3

а = rα

N₁ = 2 , f₁ = PN₁/10 , 

а = 0.3

Now we will add equation 1 and 3 stated above we will get P which will be equal to 4

So the answer is 4.