Question

A boy is running on a straight road. He runs.
500 m to wards north in 2 min los and then turns
back and runs 2oom in I min. Calculate.
his average speed and magnitude of average
velocity during first 2 min los.
(ii) his average speed and magnitude of average
velocity during the whole journey.​

Answer 1

Ahoy !

Let the boy start from a point A and B point is 500 m away from it .

And a C point which is 200 m away from point B .

Now

Time taken to reach at point B.

T= 130s

Distance = 500m

avg speed = 500/ 130

= 3.7m/s

displacement = 500m

v.avg = 500 / 130

= 50 / 13

= 3.7 m/s

Total joutney's avg speed

= (500/ 130 + 200 / 60 ) / 2

= ( 3.7 + 3.3 ) / 2

= 7 / 2

= 3. 5 m/s

as we know the AC = 300m

And time taken from reaching A to C is

= 130 - 60 sec

= 70 sec

Total avg velocity

= 300 / 70

= 4.2 m/s

May it helps you :)

Answer 2

Answer:

hi army good news!!!!!!!!!!!!