A boy is standing on the edge of the roof at height 78.4m. He throws a ball vertically upward with velocity of 19.6 m/s . After how much time the ball will reach the ground?. Take a= 9.8 m/s square downward.
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The total time = time taken to for the ball to reach the roof + time taken for the ball to reach the ground from the roof with velocity -19.6 m/s.
=> time to reach the roof = 2(19.6)/9.8 = 4
Now, to find the time taken to reach the ground:
initial velocity=19.6
Height=78.4 m
final velocity = ?
time=?
=> v^2 = u^2 + 2gh
Substitute the values:
=> v = sqrt(19.6^2 + 2(78.4)(9.8)
v = 43.8
To find time: v = u + at
=> 43.8 - 19.6 = 9.8t
=> t=2.47
threfore the total time= 6.47
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