Question

A boy is standing on the ground and flying a kite with 100m of string at an elevation of 30°. Another boy is standing on the roof of a 20m hight building and flying his kite at an elevation of 45°. Both the bous are on the opposite side of both the kites. Find the lenght of the string that the second boy must have so that the two kites meet. ​

Answer 1

Hola Mate♥...

AE = 100m and DC = 20m (given)

Let EF = h m

➡In right ∆ABE,

h+20/100 = sin 30°

h+20/100 = 1/2

h = 30m

➡In ∆EFD,

h/ED = sin 45°

30/ED = 1/√2

ED = 30√2 m.

i hope it will helps you❤...

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Answer 2

Answer:

Explanation:

AE = 100m and DC = 20m (given)

Let EF = h m

In right ∆ABE,

h+20/100 = sin 30°

h+20/100 = 1/2

h = 30m

In ∆EFD,

h/ED = sin 45°

30/ED = 1/√2

ED = 30√2 m.

Hope it helps u