a boy is standing on the ground and is flying a kite with 42 m of string at an elevation of 30degree another boy standing on the roof of a 12m high building and is flying the kite at an elevation of 60 degree both the boys are on opposite sides of bothes the kites find the length of string that the second boy must have so that the two kites must at a point
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tan30=
CD
AC
=>
CD
AC
=
3
1
=>LetAC=x,CD=x
3
AE=AC+CE=x+25
sin45=
2
1
=
AB
AE
=>
75
x+25
=
2
1
=> x=
2
75
2
−50
=27.85m
=> AC=27.85m,CD=48.18m
AD=
AC
2
+CD
2
=55.67m = lenght of string of second boy
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