Question

A boy leaves his home at 8:45 a.m. and walks to school 1.25 km away He arrives at school at 9:20 a.m. What is his average speed​

Answer 1

Answer:

let, V be his final speed and 0 be its initial speed

so we know,

Distance(s)= change in speed per unit time

or, s = (V - 0)/t

or, V = s × t

or, V = 1.25 × (9:20 - 8:45)/60

or, V = 0.729 km/ hr

hence, average speed of the boy = 0.729 km/ hr.

HOPE THE PROCESS IS CONVENIENT...