A boy leaves his house at 9.30 A.M. for his school. The school is 2 km. away and classes start at 10.00 A.M. If he walks at a speed of 3 km/h for the first km. at what speed should he walk the second km. to reach just in time ?
Answers
Answered by
93
distance = 2 km total time = 30 min = 0.5 hourinitial speed = 3km/h for first 1 kmHence time taken = distance/speed = 1/3 h time left = 0.5 - 1/3 = 0.5/3 hdistance left = 1 km Hence speed at which he should walk the second km would be 1/(0.5/3) = 6 km/h
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Solution:-
Given:- Total time = 30min (0.5hours)
total distance = 2km.
(A/Q)
1st Case...
Distance Travelled = 1Km
Speed= 3km/h.
time taken = 1/3 hour. ( T= distance/speed).
2nd Case....
Distance left or have to travel = 1km
Time left = 1/3×0.5 hours
= 0.5/3 hours.
Speed= distance/ time
= 1/0.5/3
= 1×3/0.5
= 3/0.5 km/h
= 6km/h
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