Question

A boy lifts a mass of 1 k.g to a height of 1m in 20 sec. The power of the boy is (take g=10m/s2)
(a) 0.1W
(b) 0.2W
(c) 0.25W
(d) 0.5W ​

Answer 1

Answer:

Power=work/time=Force×displacement/time=mass×acceleration×displacement/time=mgh/t=1×10×1/20=1/2=0.5Watt

Answer 2

The power of the boy is 0.5 W.

Explanation:

Given that,

Mass, m = 1 kg

It is lifted to a height of 1 m, h = 1 m

Time, t = 20 s

We need to find the power of the boy. The rate at which work is done is called power of an object. It is given by the formula as :

$P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{1\times 10\times 1}{20}\\\\P=0.5\ W$

So, the power of the boy is 0.5 W. Hence, this is the required solution.

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