A boy mass 50kg running at 5m/s jumps on to a 20kg trolley travelling in the same direction at 1.5m/s.find their common velocity
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for the boy and trolley system nethorizontal force is 0
so momentum conservation could be applied as a sake of inelastic collision(as boy sticks up to it)
50×5 + 20 × 1.5 = (20 + 50)× v
v= 4m/s
hope this helped
so momentum conservation could be applied as a sake of inelastic collision(as boy sticks up to it)
50×5 + 20 × 1.5 = (20 + 50)× v
v= 4m/s
hope this helped
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