Physics, asked by Parvani3746, 29 days ago

A boy moves with a speed of 8 km perfect hour in 3 hours and in next in 2 hours with speed of 6 km per hour find the average speed and moved

Answers

Answered by deepakkumar114866
0

Answer:

average speed is 8km+6km/2 = 7km/per hour

Answered by anchal1463636
0

Answer:

Average speed of the boy is 7.2 km/h.

Explanation:

♡In the first 3 hours.

Speed of the boy = 8km/h.

☆Let the distance covered by the boy in the first three hours be = D¹.

☆Let the time taken by the boy to cover the distance( D¹) in the first three hours be = T¹.

☆Let the speed of the boy in the first three hours be = S¹.

¤ Distance covered by the boy in the first three hours = D¹.

¤ Time taken by the boy to cover the D¹ distance in the first three hours = 3h.

¤ Speed of the boy in the first three hours = 8km/h.

● Speed of the boy in the first three hours.

S¹ = D¹/T¹.

8km/h = D¹/3h.

8 × 3 = D¹.

24km = D¹.

D¹ = 24km.

Distance (D¹) covered by the boy in the first three hours is 24km.

♡In the next two hours.

Speed of the boy = 6km/h.

☆Let the distance covered by the boy in the next two hours be = D².

☆Let the time taken by the boy to cover the distance(D²) in the next two hours be = T²

☆Let the speed of the boy in the next two hours be = S².

¤ Distance covered by the boy in the next two hours = D².

¤ Time taken by the boy to cover the distance(D²) in the next two hours = 2h.

¤ Speed of the boy in the next two hours = 6km/h.

● Speed of the boy in the next two hours.

S² = D²/T².

6km/h = D²/2h.

6 × 2 = D².

12km = D².

D² = 12km.

Distance(D²) covered by the boy in the next two hours is 12 km.

● Average speed of the boy = Total distance covered/Total time taken.

Average speed of the boy = D¹+D²/T¹+T².

Average speed of the boy = 24km+ 12km/3h + 2h.

Average speed of the boy = 36km/5h.

Average speed of the boy = 7.2km/h.

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