Question

a boy of mass 40 kg climbs up a rope with an acceleration of 2ms-2 . What is the tension in the rope

Answer 1

T-mg=ma

T=ma+mg

T=40(2+10)

T=480N

Answer 2

Answer: 472 N

Explanation:

The tension in a rope is given by :-

$\text{Tension}=ma-mg=m(a-g)$, where  m is the mass and a is acceleration and g is the acceleration due to gravity ($9.8\ ms^{-2}$).

Given : The mass of the boy climbs up a rope= 40 kg

The acceleration = $a=2\ ms^{-2}$

Then, the tension in the rope will be :-

$\text{Force }=40(2+9.8) = 472\ \text{N}$

Hence, the tension in the rope =  472 N