A boy of mass 40kg is hanging from the horizontal branch of a tree. the tension is his arms is minimum when the angle between the arm is.
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Heya!!
Here's your answer!!
Let 2θ be the angle between the arm
2T cos θ = mg
T = mg/2cosθ
Tension when cos θ is mass. this achieved when θ = 0
T = mg/2 = 40×10/2
= 200 N
The both arm should be parallel ..ll.e. either 0 or 360.
Glad help you
it helps you
thank you
@vaibhavhoax
#born with attitude
Here's your answer!!
Let 2θ be the angle between the arm
2T cos θ = mg
T = mg/2cosθ
Tension when cos θ is mass. this achieved when θ = 0
T = mg/2 = 40×10/2
= 200 N
The both arm should be parallel ..ll.e. either 0 or 360.
Glad help you
it helps you
thank you
@vaibhavhoax
#born with attitude
Answered by
37
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