a boy of mass 40kg jumps with a horizontal velocity of 5m/s onto a stationary cart with frictionless wheels. the mass of the cart is 3kg. what is his velocity as the cart starts moving.
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Answer:
The cart starts moving with velocity 4.65 m/s
Explanation:
According to law of conservation of momentum
m₁u₁ + m₂u₂ = (m₁+m₂) v
40 x 5 + 3 x 0 = 43 x v
v = 200/43
= 4.65 m/s
∴ The cart starts moving with velocity 4.65 m/s
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