Question

A boy of mass 50 kg standing on ground exerts a force of 500 N on the ground. The force exerted by the ground on the boy will be:
(a) 50 N
(b) 25000 N
(c) 10 N
(d) 500 N

Answer 1

Explanation:

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Answer 2

Gudnyt

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We know that there is no net movement for the boy ie,

the boy is neither going up by the force exerted by ground nor

the ground is going down by the force exerted by the

Hence net force = 0 ie,

Force exerted by ground + Force exerted by boy = 0

Force exerted by ground + 500N = 0

Force exerted by ground = -500N

Here the -ve sign indicates that the force is in the opposite direction as of the force exerted by the boy

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