Question

A boy of mass 50kg .Tum with a velocity of 2ms.He jump on it a cort of 2kg while running.find the velocity as which the called the boy jump on it​

Answer 1

Formula M1u1+m2u2={M+m]v2  

M=50kg,u1=2m/s,m=2kg,u2=0

After jumping on to cart both man and cart move with common velocity.So

by substituting values we get,

50(2)+2(0)=(50+2)v2

100+0=52v2

v2=100/52=1.9

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