the digit at tens place of a two digit number is three times the digit at ones place is the sum of this number and the number formed by reversing the digit is 88 find the number
Answers
Answered by
1
Solution :-
Let the digit at tens place be x and the digit unis place be y.
Then the original number will be 10x+y.
The digit at tens place is three times the digit at the units place.
i.e. x=3y ....(1)
The sum of this number and the number formed by reversing its digits is 88.
(10x+y)+(10y+x)=88
⇒11x+11y=88
⇒x+y=8 ....(2)
Substitute the value of equation (1) in equation (2).
Therefore, 3y+y=8
⇒4y=8
⇒y=2
Therefore, x=3y=3×2=6
Therefore, the original number is 62.
Hence the number is 62.
Hope it is helpful to you ☺️
Answered by
1
Answer:
62
Step-by-step explanation:
Let the units digit be x.
Tens digit = 3x
Original number = 10(3x)+x = 30x+x = 31x
After reversing digits,
Units digit = 3x
Tens digit = x
New number = 10x+3x = 13x
According to Question,
31x+13x = 88
=> 44x = 88
=> x = 2
Hence, the original number is 62.
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