A boy of weight 25kg slides down a rope hanging from the branch of a if frictional force against him is 50N , acceleration Of boy is
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By drawing FBD we can say
mg - T = ma
a = (mg - T) / m
= ([(25 × 10) - 50] / 25
= 8 m/s^2
Acceleration of boy is 8 m/s^2
mg - T = ma
a = (mg - T) / m
= ([(25 × 10) - 50] / 25
= 8 m/s^2
Acceleration of boy is 8 m/s^2
happyliferakesowv3qf:
Thanks for your answer
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