a boy osberves thats the angle of elevation of the top of a tower is32 .he then walks 8m towaret the angle of evevation is 43 find the height of the tower
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Given:
angle of elevation when distance of boy from tower is taken to be x=32
Angle of elevation when distance of boy from tower is (x-8)=43
To find:
Height of the tower
Solution:
Let's assume the height of the tower to be 'h'
Now, taking case 1, we have:
tan32=h/x
h=x(tan32) (1)
Next, taking case 2, we have:
tan43=h/(x-8)
h=(x-8)(tan43) (2)
Now, equating equations (1) and (2), we get:
h=x(tan32)=(x-8)(tan43)
Putting values of tan32=0.625 and tan43=0.933, the equation becomes:
0.625x=0.933x-7.46
x=24.22m
Now, putting this value of x in equation (1), we get:
h=x(tan32)
h=24.22*0.625
h=15.13m
Therefore, height of tower (h)=15.13m
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