a boy pulling box of mass 10 kg what is normal force acting on also find the frictional force if the coefficient of friction u is 0.3
Answers
Answered by
7
Answer:
Normal force (N) = mg
= 10 * 10 = 100 N
Frictional force (f) = umg
= 0.3*10*10
= 30 N
I hope it helps .
Answered by
1
Answer:
Normal force (N) = mg
10*10 = 100N
frictional force (f) = umg
0.3*10*10 =30N
Answer = 30N
Explanation:
Similar questions