Question

A boy pushes a wall with force of 20n what magnitude and direction of the force experience by the body

Answer 1

The boy will experience the same for force of 20n in his opposite direction.because of newtons 3rd law I.e. every action has an equal and opposite reaction.



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Answer 2

The magnitude of the force experienced by the boy is 20 N and the direction is opposite to the direction of force exerted by the boy on the wall.

Given,

Force with which a boy pushes the wall, F = 20 N

To Find,

The force experienced by the boy

Solution,

This problem could be solved using a very simple method.

We use Newton's Laws of Motion for solving this problem.

Newton's Laws of Motion are as follows:

Law 1: "A body remains at rest, or in motion at a constant speed in a straight line, unless acted upon by a force."

Law 2: "When a body is acted upon by a force, the time rate of change of its momentum equals the force."

Law 3: "If two bodies exert forces on each other, these forces have the same magnitude but opposite directions."

In the given scenario, a boy pushes a wall with a force of 20 N.

Since a wall does not move, we must assume that a force is exerted by the wall on the body, to resist the force exerted by the boy.

According to Newton's Third Law of Motion, this force is equal in magnitude to the force exerted by the boy.

But the direction is opposite to the direction of the force exerted by the boy.

Therefore, the force exerted by the wall on the boy, F' = -20 N

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