a boy ran for 2 hours 13 Minutes in a race but the announcer wrongly announced this as 2 hour 31 minutes find the percentage error
insiyahr:
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Answered by
41
Answer:
13.53%
Step-by-step explanation:
Given that a boy ran for 2 hours 13 minutes = 133 minutes.
Given that wrongly announced as 2 hour 31 mins = 151 minutes.
Error = (151 - 133)
= 18.
% Error = (18/133) * 100
= 1800/133
= 13.53%.
Therefore, Percentage error = 13.53%.
Hope it helps!
Answered by
1
Answer:
2 hrs 13 mins = 133 mins
and 2 hrs 31 mins = 151 mins
% error = error time - actual time ÷ actual time × 100%
% error = 151-133/133×100%
% error = 18/133×100%
% error = 13.53
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