Math, asked by insiyahr, 10 months ago

a boy ran for 2 hours 13 Minutes in a race but the announcer wrongly announced this as 2 hour 31 minutes find the percentage error


insiyahr: Write with proper steps

Answers

Answered by siddhartharao77
41

Answer:

13.53%

Step-by-step explanation:

Given that a boy ran for 2 hours 13 minutes = 133 minutes.

Given that wrongly announced as 2 hour 31 mins = 151 minutes.

Error = (151 - 133)

        = 18.


% Error = (18/133) * 100

            = 1800/133

            = 13.53%.


Therefore, Percentage error = 13.53%.


Hope it helps!

Answered by skalam306
1

Answer:

2 hrs 13 mins = 133 mins

and 2 hrs 31 mins = 151 mins

% error = error time - actual time ÷ actual time × 100%

% error = 151-133/133×100%

% error = 18/133×100%

% error = 13.53

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