A boy read 2/7th of a book on one day and 4/5th of the remainder on another day . If there were 12 pages unread . How many pages are there in the book.
Answers
Answered by
8
Step-by-step explanation:
Let the total number of pages be x
First day = 2/7 of x = 2/7*x= 2x/7
Remaining pages= x-2/7=5x/7
Another day=4/5 of 5x/7=4x/7=X/7
Also remaining pages =12
So X/7=12
X=12*7=84 pages
The book contains 84 pages
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Answered by
1
Step-by-step explanation:
Let the total number of pages be x
First day = 2/7 of x = 2/7*x= 2x/7
Remaining pages= x-2/7=5x/7
Another day=4/5 of 5x/7=4x/7=X/7
Also remaining pages =12
So X/7=12
X=12*7=84 pages
The book contains 84 pages
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