Math, asked by divishajindal1226, 1 year ago

A Boy read 3/8 of the book on one day and 4/5 of the remainder on the other day if there were 30 pages unread,how many pages did the book contain?

Answers

Answered by sidd200
9
let total pages be x
Book read on first day = 3x/8
book read on 2nd day =( 5x/8 )4/5
unread pages = 30
x = 3x/8 + 1x/2 + 30
30 = x -3/8x - 1/2x
30 = 8x-3x-4x/8
x = 30×8
= 240 pages
Answered by shaurya4534
5
Let Total Pages = X.
First Day Read = 3/8 * X
Second Day Read,
(X - 3X/8) * 4/5 = X/2
Remaining = 30 Pages.
Total Pages = First day Read + Second Day Read + remaining Pages
X = 3X/8 + X/2 + 30
X - 3X/8 - X/2 = 30
(8X - 3X - 4X)/8 = 30
X = 30 * 8
X = 240.
Total Page = 240.
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