Question

A boy read 3/8th of a book one day and 4/5th of the of the remaining pages the other day. If there were 30 pages unread, how many pages did the book contain?​

Answer 1

Answer:

Please mark me the brainliest.

Step-by-step explanation:

Let us consider the total number of pages in the book to be ‘x’.

It is given in the question that a boy read 38th of a book on day 1. Since we have ‘x’ number of pages in the book, we can say that the pages that the boy read on day 1 would be –

⇒x×38=3x8

Now, we can write that the remaining pages would be –

=x−3x8

By taking the LCM, we get –

8x−3x8=5x8

It is also given that, On other day he read 4th5 of remaining pages.

i.e. (5x8)(45)=20x40

=x2

We can get the total numbers of pages read on both the days by adding the results as below -

3x8+x2

By taking the LCM of 8 and 2, which is 8, we get –

⇒3x8×8+x2×8=3x+4x8=7x8

Now, we will find the numbers of remaining pages unread. So, we can subtract it from x as,

x−7x8

By taking LCM, we get –

8x−7x8=x8

According to the question the remaining unread pages are 30.

So, we can equate as x8=30

By multiplying 8 on both sides, we get –

x=240

Hence, the total no. of pages in the book is 240.

Note: Students get confused while understanding the question. They need to be very careful while reading and understanding the question. Here in this question it is given that 4th5 of the remaining book is read on other day, which means we have to find the numbers of pages read on other day by multiplying 4th5 with remaining unread pages of the book.

Answer 2

Answer:

240

Step-by-step explanation:

Please mark the answer as brainliest