Question

a boy records that 4000 joule of work is required to transfer 10 coulmb of charge between two parts of a reaistor of 50 ohm . the current passing through it is?​

Answer 1

Answer:

9 A

Explanation:

W = (V) ^2/r

4000=(v)^2/50

4000*50 = v^2

447.2 = v

447(estimation)

V = Ir

447/50 = I

8.94 A =I

Or 9 A (estimation)

Answer 2

The current passing through the resistor is 8.94 A

Given:

Work = 4000 joule

Charge = 10 coulomb

Resistance = 50 ohm

Find: The current passing through the resistor

Solution:

We know,

According to Ohm's Law,

work or power,

W = V²/R

Voltage = V, Resistance = R

4000 = V²/50

∴ V² = 4000*50

        = 200000

∴ V = √200000

     = 447.213

      ≈ 447

So the voltage (V) = 447 V

Now we also know that V = IR

I = V/R

 =447/50

 = 8.94 A

Hence the current passing through the resistor is 8.94 Amperes.

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