Question

A boy runs on a circular path of radius R = 2811 with a constant speed 1 = 4m/s. Another
boy starts from the centre of the path to catch the first boy. The second boy always
remains on the radius connecting the centre of the circle and the first boy and maintains
magnitude of his velocity a constant V = 4m/s. If the time of chase is( 10+x) sec thien x=--​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

Given:

The radius of a circle = 2811

speed  = 4m/s

Let the time taken be 'x' seconds

Another boy runs from the centre of the path to catch the first boy.

Total distance = 2 π r = 2 x 22/7 x 2811 = 17669.1429

Total speed = 4m/s

Time gap = (10 + x)

We know,

Distance = speed X time

17669.1429 = 4 X (10 + x)

17669.1429/4 = 10 + x

4417.2853 = 10 + x

4417.2853 - 10 = x

Or x = 4417 seconds approximately.