Question

A boy's age is one-fourth that of his father.
After 24 years the boy will be half the age of
his father. Find their present ages.


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Answer 1

Answer:

Step-by-step explanation:

Let the age of father be x.

Then son's age = x/4.

After 24 years

Father's age = x +24

Son's age = x/4 +24

A.T.Q.

x/4 +24 = x+24/2

x+96/4=x+24/3

2(x+96)=4(x+24)

2x +192=4x+ 96

192-96=4x-2x

96=2x

x=48.

So the present age of father is 48 and son's age is 1/4 ×48=12 years.

Answer 2

Hope it is helpful to you