Question

The edge length of fcc unit cell is 508 pm. If radius of cation is 110 pm the radius of anion is

Answer 1

For an fcc solid, edge length , $ a = 2(r^+ + r^-)$

$\Rightarrow2(110 + r^-) = 508$

$\Rightarrow220 + 2r^- = 508$

$\Rightarrow2r^- = 508 - 220$

$\Rightarrow2r^- = 288$

$\therefore r^- = 144pm$

Hence answer is (d)

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