Question

A boy save rs 1.25 pe day . what is least number of days in which he will be able to convert his savings into rs 50 note

Answer 1

Solution :-

Rs. 4.65 = 465 paise

The exact number of rupees will be a multiple of 100

So, we have to fine the L.C.M. of 465 and 100

100 = 2*2*5*5

465 = 3*5*31

L.C.M. of 465 and 100 = 2*2*3*5*5*31

= 9300

So, the boy saves 9300 paise

Hence, least number of days required to save 9300 paise = 9300/465

= 20 days

Answer.

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Answer 2

50/1.25= 40 days ujjjjj