a boy saves ₹ 4.65 daily. find the least number of day in which he will be able to save an exact number of rupees
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Answers
Answered by
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The least number of days is 20 to save an exact number of rupees
Since 4.65×20=46.5×2=93
Since 4.65×20=46.5×2=93
Danish8881:
bhai iska answer 20 aana h
please solve kro
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Solution-
Rs. 4.65 = 465 paise
The exact number of rupees will be a multiple of 100.
So, we have to find the LCM of 100 and 465.
100 = 2 × 2 ×5 × 5
465 = 3 × 5 × 31
LCM of 100 and 465 = 2 × 2 × 3 × 5 × 5 × 31 = 9300
So, the boy saves 9300 paise.
Hence, number of days required
= 9300/465
= 20 days
Answer.
Rs. 4.65 = 465 paise
The exact number of rupees will be a multiple of 100.
So, we have to find the LCM of 100 and 465.
100 = 2 × 2 ×5 × 5
465 = 3 × 5 × 31
LCM of 100 and 465 = 2 × 2 × 3 × 5 × 5 × 31 = 9300
So, the boy saves 9300 paise.
Hence, number of days required
= 9300/465
= 20 days
Answer.
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