Question

: A boy saves Rs 4.65 daily find the least number of days in which he will be able to save an exact number of rupees?
please solve krk dikhao

Answer 1

Solution :-

Rs. 4.65 = 465 paise

The exact number of rupees will be a multiple of 100

So, we have to fine the L.C.M. of 465 and 100

100 = 2*2*5*5

465 = 3*5*31

L.C.M. of 465 and 100 = 2*2*3*5*5*31

= 9300

So, the boy saves 9300 paise

Hence, least number of days required to save 9300 paise = 9300/465

= 20 days

Answer.

Answer 2

Answer:

Answer is 20

Step-by-step explanation:

First see the no. 4.65.

∴ If you divide it by any single no. like 2, 3, 4, 8 etc. You will get a no. in point.

Think it from a wider angle of view. Just use common sense. Its so simple

Suppose take days be 10

∴ 4.65 * 10=46.5, so it is not an exact no.

Again, If you try to solve it by using any no. from 10 to 19. you would not get your answer.

So, at last try it by 20.

⇒4.65*20= 93.00

∴ It will be in 20 days.

Thank you