Question

A boy saves rs 4.65 daily find the least number of days in which he will able to save an exact number

Answer 1

Answer:

20 days.

Step-by-step explanation:

Rs.4.65 = 465 Paise .

The exact number of rupees will be a multiple of 100 ,

So, We have to find the L.C.M. of 465 and 100  :

100 = 2×2×5×5 .

465 = 3×5×31 .

L.C.M. of 465 and 100 = 2×2×3×5×5×31 = 9300 .

So, The boy saves 9300 paise.

∴ Hence, least number of days required to save 9300 paise =

9300/465 = 20 days.