Question

A boy saves Rs1.75 per day find the least number of days in which he will be able to convert his savings into Rs.10 note​

Answer 1

Answer:

Step-by-step explanation:

Let his saving on day one is 1.75

Second day it will be 1.75×2

So on

Now it forms an AP

a=1.75 d=1.75 last amount is 10.

l=a+(n-1)d

10=1.75+(n-1)1.75

10-1.75=1.75n-1.75

10-1.75+1.75=1.75n

10=1.75n

10/1.75=n

5.714....

~6 days

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