A boy slides on his skateboard on a special curved track. It starts from the top 3.9 m of the track and reaches the lowest level with a speed of 6.2 m / s. What work did the frictional force do on him? The boy and his skateboard weigh 43 kg
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The initial mechanical energy plus the work of the frictional force is equal to the final mechanical energy.
Ei + Tr = Ef
The initial energy is potential energy and the final energy is kinetic.
Rt = Ef-Ei = 1/2. 43 kg (6.2 m / s) ² - 43 kg. 9.80 m / s². 3.9 m = -817 J
The friction work is always negative.
Ei + Tr = Ef
The initial energy is potential energy and the final energy is kinetic.
Rt = Ef-Ei = 1/2. 43 kg (6.2 m / s) ² - 43 kg. 9.80 m / s². 3.9 m = -817 J
The friction work is always negative.
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