A boy standing at a distance of 48 meters from a building observes the top of the building and makes an angle of elevation of 30 degree . find the height of the building
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In solving this problem, we are going to use Tan∅
Tan∅ = Opposite/Adjacent
Opposite = h, the height of the building
Adjacent = 48m
∅ = 30 degrees
Tan 30 = h/48
h = 48 Tan 30
= 27.7 m
The height of the building = 27.7 m
NOTE:
The most accurate way of getting the actual height of the building is to add the height of the boy to 27.7 m
The height of the building would be = 27.7m + the height of the boy
Tan∅ = Opposite/Adjacent
Opposite = h, the height of the building
Adjacent = 48m
∅ = 30 degrees
Tan 30 = h/48
h = 48 Tan 30
= 27.7 m
The height of the building = 27.7 m
NOTE:
The most accurate way of getting the actual height of the building is to add the height of the boy to 27.7 m
The height of the building would be = 27.7m + the height of the boy
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Answer:NJ
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