Question

A boy standing at the top of a tower of 80 m height drops a stone
Assuming g = 10 ms, the velocity with which it hits the ground is​

Answer 1

Answer:

40

Explanation:

s=80m (displacement)

u=0 (since it is dropped so it is in free fall)

a=g=10ms^-2

v=?

By 3rd eq of motion,

2as=v^2-u^2

2×10×80=v^2 ( u^2 will be zero)

1600=v^2

v=sq root of 1600

v=40m/s

It hits the ground with a velocity of 40

Answer 2

Answer:

your answer is below

Explanation:

it gains the speed of gravity 10 m s