A boy standing in his balcony heard the sound of lightning after 2 seconds of the flash. Calculate the distance between boy and the lightning. If speed of sound is 340m/s and speed of light is 3*10^8m/s.
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Answered by
1
Distance= speed of sound × time
2d= v×t
2d=340×2
2d=680
d=680÷3
d=340m
Answered by
0
Answer:
680m
Explanation:
let the lightning is seen by the boy in x seconds.
d=S×T
d=3×10^8×x ------------eq.1
If lightning takes x seconds.Then the time taken by sound acc. to ques is (x+2)sec
Thus,ď=S×T
ď=340×(x+2) ---------eq.2
As,the distance will be same(d=ď) in both cases of light and sound so by equating eq.1 and eq.2 we get,
3×10^8×x=340×(x+2)
by solving this eq. we get 680/3×10^8=x
Then put x in eq.1 we get d=ď=680m
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